This is from an old post in roulette forum by user reddwarf. I tried to create the same situation with dozen 2 but the numbers are not correct. Can anyone find the way this is done?To illustrate what I mean: lets create an example roulette game and try to meet all above requirements. please note this is just an example,not a winning strategy!! It just illustrates how we can use the features to build a method + some bonus info on which I will never elaborate!!

Session: we start at will, we stop when 3 unique dozens have appeared

negative permutations: repeats of previous dozens!, zero's or a combination

Lets define the betting unit U as 4*b, b=base bet, 1 dollar, 10 cents or whatever. So in our system 1 unit = 1U =4*basebet

bet1:

if previous dozen=1 or 3: bet 0.5 units on dozen, bet 0.25 on line that completess the half, bet 0.25 on the zero and bet 1.5 units on the oppisite half

if previous dozen=2: bet 0.25 on line, bet 0.5 units on dozen that completess the half, bet 0.25 on the zero and bet 1.5 units on the oppisite half

what can happen:

1. opposite half (another unique dozen): we win, technically the session is not ended, but we end it anyway

2. zero, we win, technically session is not ended, but we end it anyway

3. covered dozen -> we win 0.75 units on the negative permutation, so overall we lose 0.75 units (instead of the 1.5 units we would have lost without covering the negative permutations

spin2:

if zero falls, or the previous dozen repeats, we can repeat the previous bets

if the line falls we cover the previous 2 dozens + the zero (with 0.25 units) + the half that contains the dozen not yet fallen

Dozen 13 came out, so....

zero ----- .25 ---------wins 4.25(minus .25) ----------If outcome Profit 1.75

Line 3 --- .25 ---------wins 1.25(minus .25) ----------If outcome Lose 1.00

Dozen 1 - .50 ---------wins 1.00(minus .50) ----------If outcome lose 1.00

High ----- 1.50 --------wins 1.50(minus 1.50) -------- If outcome Profit .50

How he got .75 win/lose? Where did i mess up?